Question #173537

7. a) How many numbers form 0 to 999 (0 and 999 inclusive) are indivisible by 7 or 11?


1
Expert's answer
2021-04-29T11:57:21-0400

Solution.

Numbers which divisible by 7:

an=a1+(n1)d,a_n=a_1+(n-1)d,

a1=0,d=7,an=994,a_1=0,d=7,a_n=994,

from here n=143.n=143.

Numbers which divisible by 11:

an=a1+(n1)d,a_n=a_1+(n-1)d,

a1=0,d=11,an=990,a_1=0,d=11,a_n=990,

from here n=91.n=91.

Numbers which divisible by 7 and 11:

an=a1+(n1)d,a_n=a_1+(n-1)d,

a1=0,d=77,an=924,a_1=0,d=77,a_n=924,

from here n=13.n=13.

Numbers which divisible by 7 or 11:

143+9113=221.143+91-13=221.

Numbers which are not divisible by 7 or 11:

1000221=779.1000-221=779.

Answer. 779.


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