Question #173527

3. a) If the solution of the recurrence relation αun−1 +βun−2 = f(n),(n ≥ 2) is

un = 1−2n+3.2

n

, then determine the values of α,β and f(n).


1
Expert's answer
2021-04-15T07:28:01-0400

Given recurrence relation is-

αun1+βun2=f(n)αu_{n−1} +βu_{n−2} = f(n)


Also, un=12n+3.2nu_n=1-2n+3.2^n


For solving such equation the value of coefficient is 1 so α=1,β=1\alpha=1,\beta=1

The solution of the above equation can be written by characterstics root method as-

un=c1+c2n+3.2nu_n=c_1+c_2n+3.2^n


The value of f(n) must be the value of the nin homogeneous part of the solution i.e. f(n)=3.2nf(n)=3.2^n


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS