Question #173527

3. a) If the solution of the recurrence relation αun−1 +βun−2 = f(n),(n ≥ 2) is

un = 1−2n+3.2

n

, then determine the values of α,β and f(n).


Expert's answer

Given recurrence relation is-

αun1+βun2=f(n)αu_{n−1} +βu_{n−2} = f(n)


Also, un=12n+3.2nu_n=1-2n+3.2^n


For solving such equation the value of coefficient is 1 so α=1,β=1\alpha=1,\beta=1

The solution of the above equation can be written by characterstics root method as-

un=c1+c2n+3.2nu_n=c_1+c_2n+3.2^n


The value of f(n) must be the value of the nin homogeneous part of the solution i.e. f(n)=3.2nf(n)=3.2^n


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