Let's write the expression in conjunctive normal form:
x1∨x2∧x3∨x4=x1∨x4∨x2∧x3=(x1∨x2∨x4)∧(x1∨x3∨x4)
x1,x2∧x3,x4 are elementary conjunctions, so the expression is already written in disjunctive normal form: x1∨x2∧x3∨x4=x1∨(x2∧x3)∨x4
Answer: CNF: (x1∨x2∨x4)∧(x1∨x3∨x4) , DNF: x1∨(x2∧x3)∨x4
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