Question #136838
Show that if A and B are sets with the same cardinality, then |A|<=|B| and |B|<=|A|
1
Expert's answer
2020-10-22T18:04:58-0400

We say that XY|X|\leq |Y| if there is an injection i:XYi: X\to Y. If the sets AA and BB are of the same cardinality, then there exists a bijection f:ABf:A\to B. Since each bijection is an injection, ff is an injection, and therefore AB|A|\leq |B|. The inverse function f1:BAf^{-1}:B\to A is a bijection as well. Consequently, f1f^{-1} is an injection. We conclude that BA|B|\leq |A|, and we are done.


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