Question #136838

Show that if A and B are sets with the same cardinality, then |A|<=|B| and |B|<=|A|

Expert's answer

We say that ∣X∣≤∣Y∣|X|\leq |Y| if there is an injection i:X→Yi: X\to Y. If the sets AA and BB are of the same cardinality, then there exists a bijection f:A→Bf:A\to B. Since each bijection is an injection, ff is an injection, and therefore ∣A∣≤∣B∣|A|\leq |B|. The inverse function f−1:B→Af^{-1}:B\to A is a bijection as well. Consequently, f−1f^{-1} is an injection. We conclude that ∣B∣≤∣A∣|B|\leq |A|, and we are done.


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