Prove that 3Z is infinite
We known that "\\Z = \\{ ... , - 3,-2,-1,0,1,2,3, ... \\}" .
Hence, "3\\Z = 3 \\times\\{ ... , - 3,-2,-1,0,1,2,3, ... \\} = \\{ ... , - 9,-6,-3,0,3,6,9, ... \\}" .
By completeness property of real numbers, for every "k \\in \\R" , "\\exist \\ n \\in \\Z : n \\geq k" . Hence, "\\Z" is an infinite set.
Since, "\\Z" is an infinite set, so scalar multiple of "\\Z" is also infinite set. Hence, "3\\Z" is an infinite set.
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