Answer to Question #133153 in Discrete Mathematics for Amarjeet

Question #133153

Prove that 3Z is infinite


1
Expert's answer
2020-09-16T19:24:22-0400

We known that "\\Z = \\{ ... , - 3,-2,-1,0,1,2,3, ... \\}" .

Hence, "3\\Z = 3 \\times\\{ ... , - 3,-2,-1,0,1,2,3, ... \\} = \\{ ... , - 9,-6,-3,0,3,6,9, ... \\}" .


By completeness property of real numbers, for every "k \\in \\R" , "\\exist \\ n \\in \\Z : n \\geq k" . Hence, "\\Z" is an infinite set.

Since, "\\Z" is an infinite set, so scalar multiple of "\\Z" is also infinite set. Hence, "3\\Z" is an infinite set.


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