Question #132604
Give an example to prove that intersection of denumerable sets need not be denumerable
1
Expert's answer
2020-09-14T11:19:01-0400

consider the set

A={2,4,6,8,...........}A=\{ 2,4,6,8,...........\}

== set of all even natural numbers

B={1,3,5,7,.............}B=\{ 1,3,5,7,.............\}

== Set of all odd natural numbers

Now define maps

f:NA and g:NBf:\N \rightarrow A \ and \ g:\N\rightarrow B

By f(n)=2n and g(n)=2n1f(n)=2n \ and \ g(n)=2n-1

Clearly , f and gf \ and \ g are one-one and onto .

Therefore , A and BA \ and \ B are denumerable.

But AB=A\cap B=\empty , which is not an infinite set .

Hence AB=A\cap B=\empty is not a denumerable set.


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