Given A and B are two set with same number of elements, then if function A to B is one-one then that function is onto and hence invertible.
Now, f1 = {(a,1), (b,2), (c,3), (d,4), (e,5), (f,6)} and f4 = {(a,6), (b,5), (c,1), (f,2), (d,4), (e,3)} are invertible function, since they are one-one functions.
Given f2 are not one-one function since a and d have same image 2 under f2
and f3 are not one-one function since b and c have same image 3 under f3.
Inverse of function f1 = {(1,a), (2,b), (3,c), (4,d), (5,e), (6,f)}.
Inverse of function f2 = {(6,a), (5,b), (1,c), (2,f), (4,d), (3,e)}.
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