Question

1. (a) Let A = {1,2,3,4} and B={0,3,6,8,12,15}. Consider a rule f(x) = x
2 − 1, x ∈ A. Is f be a
function from A to B?

Answer 1

Using f (x) = x² - 1, x ∈ A we have

f(1) = 0,

f(2) = 3,

f(3) = 8,

f(4) = 15

We observe that every element in set A has unique image in set B.

Therefore, f is a function from A to B.