Question #116069
The binary operation on Z given by x
mathrmast (y=1+xy) not in the question later appered when i pasted)
is______ but not associative
a.Associative
b.Commutative
c.Distributive
d.Additive
1
Expert's answer
2020-05-26T19:21:56-0400

Let y=1+xyy=1+xy then

xy=y1xy=y-1

The binary operation is not associative :

(xy)zx(yz)(xy)z=(y1)z=yzz=z1z=1x(yz)=x(z1)=xzx=z1x(xy)z\neq x(yz)\\ (xy)z=(y-1)z=yz-z=z-1-z=-1\\ x(yz)=x(z-1)=xz-x=z-1-x

The binary operation is not commutative: 

xyyxxy=y1yx=x1xy\neq yx\\ xy=y-1\\ yx=x-1

The binary operation is not distributive:

(x+y)zxz+yz(x+y)z=z1xz+yz=xz+yz=z1+z1=2z2z(x+y)zzx+zyz(x+y)=x+y1zx+zy=x1+y1=x+y2(x+y)z\neq xz+yz\\ (x+y)z=z-1\\ xz+yz=xz+yz=z-1+z-1=2z-2\\ z(x+y)z\neq zx+zy\\ z(x+y)=x+y-1\\ zx+zy=x-1+y-1=x+y-2\\

 The binary operation is additive

Answer d


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