f) P ↔ (Q ∧ ¬Q) is True.
P↔(Q∧¬Q)≡P↔FP ↔ (Q ∧ ¬Q) \equiv P ↔ FP↔(Q∧¬Q)≡P↔F ; where F denotes False.
⟹ P↔(Q∧¬Q)≡T≡P↔F\implies P ↔ (Q ∧ ¬Q) \equiv T \equiv P ↔ F⟹P↔(Q∧¬Q)≡T≡P↔F
Thus, P must be False as well.
Option 3 is the correct answer.
g) The option 1 is correct as it translates to P→Q;P ⟹ QP \to Q; P \implies QP→Q;P⟹Q This simply a rule of inference known as Modus Ponens.
Option 1 is the correct answer.
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