Answer to Question #110327 in Discrete Mathematics for Ramu

Question #110327
In boolean algebra, proof: (a) x∨y = y if and only if x∧y = x
1
Expert's answer
2020-04-21T13:45:43-0400

"1)\\;if\\;x\\wedge y\\;=\\;x:\\\\0\\wedge0=0\\Rightarrow0\\vee0=0\\;Correct\\\\0\\wedge1=0\\Rightarrow0\\vee1=1\\;Correct\\\\1\\wedge0=0\\Rightarrow doesn't\\;meet\\;requirement\\;\\\\1\\wedge1=1\\Rightarrow1\\vee1=1\\;Correct\\\\2)\\;if\\;x\\vee y=y:\\\\0\\vee0=0\\Rightarrow0\\wedge0=0\\;Correct\\\\0\\vee1=1\\Rightarrow0\\wedge1=0\\;Correct\\\\1\\vee0=1\\Rightarrow doesn't\\;meet\\;requirement\\\\1\\vee1=1\\Rightarrow1\\wedge1=1\\;Correct"

So, checking both cases when one condition true, we get second condition also being true.


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