Determine the unique solution of the initial value problem.
Solution
For given homogeneous equation the characteristic equation is
λ2 - 2λ + 1=0 => (λ-1)2 => λ1,2 = 1
So the solution of homogeneous equation is y(x) = C1ex+C2xex, where C1, C2 are arbitrary constants.
From initial conditions y(0)=7,y′(0)=4 we’ll get
C1 = 7, C1 + C2 = 4 => C1 = 7, C2 = -3
So the unique solution is y(x) = 7ex – 3xex
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