xdxdy=x2+5y
y’−5xy=x (1)
Let’s solve the following equation
y’−5xy=0
ydy=5xdx
y=C(x)x5
To find solution of the equation (1) we should think C is a function of x
y′=C′x5+5Cx4
Substitution y and y’ into (1) gives
C′x5+5Cx4−5xCx5=x
C′=x−4
C=−3x31+C1
y=(−3x31+C1)x5=−31x2+C1x5
Answer: y=(−3x31+C1)x5=−31x2+C1x5 .
Comments