Question #322860

solve px+qy=y


1
Expert's answer
2022-04-06T14:32:10-0400

px+qy=ypx+qy=y

zxx+zyy=y\frac{\partial z}{\partial x}x+\frac{\partial z}{\partial y}y=y

The auxiliary equations is:

dxx=dyy=dzy\frac{dx}{x}=\frac{dy}{y}=\frac{dz}{y}

A first characteristic equation comes from

dxx=dyy\frac{dx}{x}=\frac{dy}{y}

lnx=lny+lnC1\ln{|x|}=\ln{|y|}+\ln C_1

x=C1yx=C_1y

A second characteristic equation comes from

dyy=dzy\frac{dy}{y}=\frac{dz}{y}

dy=dzdy=dz

y=z+C2y=z+C_2

General solution of the PDE on the form of implicit equation:

Φ(C1,C2)=0\Phi(C_1,C_2)=0.

Answer: Φ(C1,C2)=0\Phi(C_1,C_2)=0 , where C1=xyC_1=\frac xy, C2=yzC_2=y-z.


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