Question #300346

show that y=c1e^x+c2e^2x is the general solution of y''-3y'+2y=0 on any interval, and find the particular solution for which y(0)=-1 and y'(0)=1


1
Expert's answer
2022-02-21T16:02:48-0500

y3y+2y=0y''-3y'+2y=0

Characteristic (auxiliary) equation


r23r+2=0r^2-3r+2=0

r1=1,r2=2r_1=1, r_2=2

The general solution of y3y+2y=0y''-3y'+2y=0 on any interval is


y=c1ex+c2e2xy=c_1e^x+c_2e^{2x}

Given y(0)=1,y(0)=1y(0)=-1, y'(0)=1


y=c1ex+2c2e2xy'=c_1e^x+2c_2e^{2x}

Then


1=c1+c2-1=c_1+c_2

1=c1+2c21=c_1+2c_2

c1=3,c2=2c_1=-3, c_2=2

The particular solution is


y=3ex+2e2xy=-3e^x+2e^{2x}

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