Verify that the given differential equation is an exact:
(3x2+2y)dx+(x-4y)dy=0
To verify if the given differential equation is exact,
Give the equation
"(3x^{2}+2y)dx+(x-4y)dy=0"
"where"
"M=3x^{2}+2y" and
"N=x-4y"
For exactness, we know that
"\\frac{\u2202M}{\u2202y}=\\frac{\u2202N}{\u2202x}"
Now, we shall find "\\frac{\u2202M}{\u2202y}"
"\\frac{\u2202M}{\u2202y}=2"
Also, we shall find "\\frac{\u2202N}{\u2202x}"
"\\frac{\u2202N}{\u2202x}=1"
Since, "\\frac{\u2202M}{\u2202y} \u2260 \\frac{\u2202N}{\u2202x}"
Hence, the differential equation "(3x^{2}+2y)dx+(x-4y)dy=0"
Is not exact.
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