Question #205356

A certain plutonium isotope decays at a rate proportional to the amount present. Approximately 15% of the original amount decomposes in 100 years. How much amount of the substance has decayed after 600 years?


Expert's answer

Exponential Decay Model

The initial value problem for exponential decay


dAdt=kA,k>0,m(0)=m0\dfrac{dA}{dt}=-kA, k>0, m(0)=m_0

has particular solution


A(t)=A0ekt,A(t)=A_0e^{-kt},

where A0=A_0=original amount at time t=0,t=0,

k=k=relative decay rate that is constant (k>0),(k>0),

t=t= the time the isotope decays.

A(t)=A(t)= the amount that is left after time tt in years.

Given


(10.15)A0=A0ek(100)(1-0.15)A_0=A_0e^{-k(100)}

Then


ek(100)=0.85e^{-k(100)}=0.85

100k=ln(0.85)100k=-\ln(0.85)

k=0.01ln(0.85)k=-0.01\ln(0.85)

A(600)=A0ek(600)A(600)=A_0e^{-k(600)}

A(600)=A0(0.85)6A(600)=A_0(0.85)^6

ΔA=A0A(600)\Delta A=A_0-A(600)

ΔAA0A0(0.37715)\Delta A\approx A_0-A_0(0.37715)

ΔA(0.62285)\Delta A\approx (0.62285)

62.285%62.285\% of the original amount has decayed after 600 years.



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