Answer: b) "f(z) =\\frac{sinz} {z^4}" has a pole of order 3 at "z=0"
"=\\frac{1-\\frac{z^2}{3!}+\\frac{z^4}{5!}-...}{z^3}=z^{-3}(1-\\frac{z^2}{3!}+\\frac{z^4}{5!}-...)=z^{-3}\\psi(z),"
where "\\psi(z) =1-\\frac{z^2}{3!}+\\frac{z^4}{5!}-..." is holomorphic function at the point "z=0"
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