Question #91345

Find the polynomial equation over R of lowest degree which is satisfied by 1-i and 3+2i

Expert's answer

It can be proved that the unknown equation is (x(1i))(x(1+i))(x(3+2i))(x(32i))=0(x-(1-i))(x-(1+i))(x-(3+2i))(x-(3-2i))=0. Or the equivalent form x48x3+27x238x+26=0x^4-8x^3+27x^2-38x+26=0.


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