Question #170273

A company produces certain types of sophisticated item by three machines. The respective daily production figures are machine A 300 units, Machine B 450 units, and machine C 250 units. Past experience shows that the percentage of defective in the three machines are 0.1,0.2 and 0.7 respectively for machines A B and C. An item is drawn at random from a day's production and is found to be defective. What is the probability that it is not produced by machine C?


1
Expert's answer
2021-03-10T11:00:12-0500

Let E1,E2,E3E_1,E_2,E_3 is machine A,B,C


D = defective items


Total production = 300+450+250 = 1000


P(E1)=3001000P(E_1) = \dfrac{300}{1000}


P(E2)=4501000P(E_2) = \dfrac{450}{1000}


P(E3)=2501000P(E_3) = \dfrac{250}{1000}

Now,

P(DE1)=0.001P(\dfrac{D}{E_1}) = 0.001


P(DE2)=0.002P(\dfrac{D}{E_2}) = 0.002


P(DE3)=0.007P(\dfrac{D}{E_3}) = 0.007


Probability = P(E3D)P(\dfrac{E_3}{D}) = 2501000×0.0070.001375\dfrac{\dfrac{250}{1000}\times 0.007}{0.001375}


= 0.0001750.001375\dfrac{0.000175}{0.001375}


= 0.1270.127


P(not produced by machine C ) = 1 - 0.127


= 0.870.87




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