Based on the definition of convergent series, the following theorem is proved in complex analysis:
If ∏n=0∞zn converges, then limn→∞zn=1.
Let's call z~n=(1+zn). By the condition of the task:
∏n=0∞zn~=∏n=0∞(1+zn) converges ⇔limn→∞z~n=1
limn→∞(1+zn)=1
limn→∞1+limn→∞zn=1
1+limn→∞zn=1
limn→∞zn=0 Q.E.D.
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Prove that for Re(s) >1,we have phi(s) =s integral from 1 to infinity f(x)/x^{s+1} dx