Question #130705
Infinite product (1+Zn) converges
Show that lim Zn=0
1
Expert's answer
2020-08-26T16:57:36-0400

Based on the definition of convergent series, the following theorem is proved in complex analysis:

If n=0zn∏^∞_{n=0} z_n converges, then limnzn=1\lim_{n→∞}{z_n}= 1.

Let's call z~n=(1+zn).\tilde{z}_n = (1 +z_n). By the condition of the task:

n=0zn~=n=0(1+zn)∏^∞_{n=0} \tilde{z_n} = ∏^∞_{n=0} (1+z_n) converges limnz~n=1\Leftrightarrow \lim_{n→∞}{\tilde{z}_n}= 1

limn(1+zn)=1\lim_{n→∞}{(1+z_n)}= 1

limn1+limnzn=1\lim_{n→∞}{1}+\lim_{n→∞}{z_n}= 1

1+limnzn=11+\lim_{n→∞}{z_n}= 1

limnzn=0\lim_{n→∞}{z_n}= 0 Q.E.D.


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Comments

Assignment Expert
27.08.20, 11:22

Dear Kay, please use the panel for submitting new questions.

Kay
27.08.20, 03:27

Prove that for Re(s) >1,we have phi(s) =s integral from 1 to infinity f(x)/x^{s+1} dx

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