Answer to Question #130705 in Complex Analysis for Penny

Question #130705
Infinite product (1+Zn) converges
Show that lim Zn=0
1
Expert's answer
2020-08-26T16:57:36-0400

Based on the definition of convergent series, the following theorem is proved in complex analysis:

If "\u220f^\u221e_{n=0} z_n" converges, then "\\lim_{n\u2192\u221e}{z_n}= 1".

Let's call "\\tilde{z}_n = (1 +z_n)." By the condition of the task:

"\u220f^\u221e_{n=0} \\tilde{z_n} = \u220f^\u221e_{n=0} (1+z_n)" converges "\\Leftrightarrow \\lim_{n\u2192\u221e}{\\tilde{z}_n}= 1"

"\\lim_{n\u2192\u221e}{(1+z_n)}= 1"

"\\lim_{n\u2192\u221e}{1}+\\lim_{n\u2192\u221e}{z_n}= 1"

"1+\\lim_{n\u2192\u221e}{z_n}= 1"

"\\lim_{n\u2192\u221e}{z_n}= 0" Q.E.D.


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Comments

Assignment Expert
27.08.20, 11:22

Dear Kay, please use the panel for submitting new questions.

Kay
27.08.20, 03:27

Prove that for Re(s) >1,we have phi(s) =s integral from 1 to infinity f(x)/x^{s+1} dx

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