Answer to Question #302189 in Combinatorics | Number Theory for ABRAHAM SALOMO P

Question #302189

Qn 1. An integer N has digital representation a1a2a3. Moreover,

ˆ None of the digits a1, a2, or a3 and none of the numbers with digital

representation a1a2, a1a3, or a2a3 is divisible by 3.

ˆ N is odd.

ˆ N is divisible by 9.

ˆ a1 ≥ a2 ≥ a3.

Determine all possible numbers N.


1
Expert's answer
2022-02-25T04:25:15-0500

 NN is odd , and none of the digits a1,a2,a_1, a_2, or a3a_3 is divisible by 33


a3=1,5,7a_3=1, 5, 7

NN is divisible by 9


a1+a2+a3=9k,k=1,2a_1+a_2+a_3=9k, k=1,2

Let a3=1.a_3=1.

a1a2a3,a_1\ge a_2 \ge a_3, none of the digits a1,a2,a_1, a_2, or a3a_3 is divisible by 33 , and none of the numbers with digital representation a1a2,a1a3,a_1a_2, a_1a_3, or a2a3a_2a_3 is divisible by 3.


a2=1,a3=7a_2=1, a_3=7

Or

a2=4,a3=4a_2=4, a_3=4

Let a3=5.a_3=5.

a1a2a3,a_1\ge a_2 \ge a_3, none of the digits a1,a2,a_1, a_2, or a3a_3 is divisible by 33 , and none of the numbers with digital representation a1a2,a1a3,a_1a_2, a_1a_3, or a2a3a_2a_3 is divisible by 3.


a2=5,a3=8a_2=5, a_3=8

Let a3=7.a_3=7.

a1a2a3,a_1\ge a_2 \ge a_3, none of the digits a1,a2,a_1, a_2, or a3a_3 is divisible by 33 , and none of the numbers with digital representation a1a2,a1a3,a_1a_2, a_1a_3, or a2a3a_2a_3 is divisible by 3.

It is impossible to find the number.


The possible numbers are 441,711,855.441, 711, 855.


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