given that n is a positive even integer, 5n + 4 will always be divisible
A. 5n
B.5
C. 2
D. 4
Let n=2k,k=1,2,3,...n=2k,k=1,2,3,...n=2k,k=1,2,3,...
Then 5n+4=10k+4=2(5k+2)=2m,m=7,8,9,...5n+4=10k+4=2(5k+2)=2m, m=7,8,9,...5n+4=10k+4=2(5k+2)=2m,m=7,8,9,...
Therefore 5n+45n + 45n+4 will always be divisible by 2.2.2.
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