True or false:
The value of the binomial coefficient (210)\displaystyle{{2}\choose{10}}(102) is zero.
Solution:
We know that (nr)=n!r!(n−r)!\displaystyle{{n}\choose{r}}=\dfrac{n!}{r!(n-r)!}(rn)=r!(n−r)!n! , where n≥r;n,r≥0n\ge r;n,r\ge 0n≥r;n,r≥0
But in (210)\displaystyle{{2}\choose{10}}(102), n=2,r=10n=2,r=10n=2,r=10 which is against the definition of binomial coefficient.
Thus, the value of (210)\displaystyle{{2}\choose{10}}(102) does not exist, neither it is zero.
Hence, given statement is false.
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