Answer to Question #236819 in Combinatorics | Number Theory for liv

Question

Find the value of each of the following quantities:

C(6,1)=

C(8,1)= 

C(10,1)=

Answer 1

$$C(6,1)=\dbinom{6}{1}=\dfrac{6!}{1!(6-1)!}=\dfrac{6}{1}=6$$

$$C(8,1)=\dbinom{8}{1}=\dfrac{8!}{1!(8-1)!}=\dfrac{8}{1}=8$$

$$C(10,1)=\dbinom{10}{1}=\dfrac{10!}{1!(10-1)!}=\dfrac{10}{1}=10$$