The equation for the instantaneous voltage across a discharging capacitor is given by v=Voe^-t/t , where Vo is the initial voltage and t is the time constant of the circuit.
The equation for the instantaneous voltage across a discharging capacitor is given by v=Voe^-t/t , where Vo is the initial voltage and t is the time constant of the circuit.
a) Draw a graph of voltage against time for Vo =12v and t=2s, between t=0s and t=10s?
b) Calculate the gradient at t=2s and t=4s?
c) Differentiate v=12e^-t/2 and calculate the value of dv/dt at t=2s and t=4s?
d) Compare answers for part b and part c?
e) Calculate the second derivative of the instantaneous voltage (d^2 v/dt^2)?