"V=(4\/3)\u03c0R^3"
Differentiate w.r.t. t
"\\frac{dV}{dt}=(4\/3)\u03c03R^2 \\frac{dR}{dt}"
"\\frac{dV}{dt}=4\u03c0R^2 \\frac{dR}{dt}"
Given that,
"\\frac{dV}{dt}=10cm^3\/second"
"R=20cm"
"10=4\u03c0(20)^2 \\frac{dR}{dt}"
"\\frac{dR}{dt}=\\frac{10}{4 \\pi \\cdot (20)^2}=0.0019cm\/second"
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1. If the radius of a circle is increasing at the rate of 4cm/sec, find the rate of the increase in the area when the radius is 12cm?
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