V=(4/3)πR3V=(4/3)πR^3V=(4/3)πR3
Differentiate w.r.t. t
dVdt=(4/3)π3R2dRdt\frac{dV}{dt}=(4/3)π3R^2 \frac{dR}{dt}dtdV=(4/3)π3R2dtdR
dVdt=4πR2dRdt\frac{dV}{dt}=4πR^2 \frac{dR}{dt}dtdV=4πR2dtdR
Given that,
dVdt=10cm3/second\frac{dV}{dt}=10cm^3/seconddtdV=10cm3/second
R=20cmR=20cmR=20cm
10=4π(20)2dRdt10=4π(20)^2 \frac{dR}{dt}10=4π(20)2dtdR
dRdt=104π⋅(20)2=0.0019cm/second\frac{dR}{dt}=\frac{10}{4 \pi \cdot (20)^2}=0.0019cm/seconddtdR=4π⋅(20)210=0.0019cm/second
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Dear hann. Please use the panel for submitting new questions.
1. If the radius of a circle is increasing at the rate of 4cm/sec, find the rate of the increase in the area when the radius is 12cm?
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Dear hann. Please use the panel for submitting new questions.
1. If the radius of a circle is increasing at the rate of 4cm/sec, find the rate of the increase in the area when the radius is 12cm?
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