Question #348773

State if the following statement is true or false. Give reasons for your answers in the form of a short proof or a counterexample.



(√2, 1, ½) E Q X Z X R.

1
Expert's answer
2022-06-08T18:03:10-0400

The statement is false because 2Q\sqrt{2}\notin\mathbb{Q}.


Proof that 2Q\sqrt{2}\notin\mathbb{Q}:

Suppose 2\sqrt{2} is rational. That mean it can be writen as the ratio of two inegers pp and qq

2=pq\sqrt{2}=\frac{p}{q} (1)

where we may assume that pp and qq have no common factors. (If there are any common factors we cancel tham in the numerator and denominator.) Squaring in (1) on both sides gives

2=p2q22=\frac{p^2}{q^2} (2)

which impiels

p2=2q2p^2=2q^2 (3)

Thus p2p^2 is even. The only way this can be true is that pp itself is even. But then p2p^2 is actually divisible by 44. Hence q2q^2 and therefore qq must me even. So pp and qq are both even which is a contradiction to our assumption that they have no common factor. The square root of 2 cannot be rational.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS