Identify the surfaces of the following equations by converting them into equations in the Cartesian form.
ρ = sin ϕ sin θ
The equation "\u03c1 = sin \u03d5 sin \u03b8" is in spherical coordinates.
To convert from spherical coordinates to rectangular coordinates there are the next equations:
"x=\u03c1sin\\phi cos\u03b8,"
"y=\u03c1sin\\phi sin\u03b8,"
"z=\u03c1cos\\phi,"
"\u03c1^2=x^2+y^2+z^2."
From the second equation we have: "sin \u03d5 sin \u03b8=\\frac{y}{\\rho},"
and we can rewrite the equation of the surface:
"\\rho=\\frac{y}{\\rho},"
"\\rho ^2=y,"
"x^2+y^2+z^2=y,"
"x^2+y^2-y+z^2=0,"
"x^2+(y-\\frac{1}{2})^2-{\\frac{1}{4}}+z^2=0,"
"x^2+(y-\\frac{1}{2})^2+z^2= \\frac{1}{4}."
This is the equation of a sphere with a center in "(0, \\frac{1}{2}, 0)" and radius "\\frac{1}{2}."
Comments
Leave a comment