Question #346425

A curve is described by 𝑦=𝑝𝑥2+𝑞𝑥, where 𝑝 and 𝑞 are constants.

a. Find an expression for the gradient of this curve at any point.

b. Given that at the point (1,−2) the gradient is 6, calculate the values of 𝑝 and 𝑞.

c. Show that the equation of the normal to the curve at the point (1,−2) can be written as 𝑥+6𝑦+11=0.


1
Expert's answer
2022-05-31T12:47:38-0400

a.

y=px2+qxy=px^2+qx

grad(y)=(px2+qx)=2px+qgrad (y)=(px^2+qx)'=2px+q

b.


2=p(1)2+q(1)-2=p(1)^2+q(1)2p(1)+q=62p(1)+q=6

q=2pq=-2-p2p2p=62p-2-p=6

p=8,q=10p=8, q=-10

c.

Find the slope of the normal at the point (1,2)(1, -2)


slope=m=1grad(y)=16slope=m=-\dfrac{1}{grad (y)}=-\dfrac{1}{6}

The equation of the normal at the point (1,2)(1,-2) is


y(2)=16(x1)y-(-2)=-\dfrac{1}{6}(x-1)

6y+12=x+16y+12=-x+1

Then he equation of the normal to the curve at the point (1,2)(1,−2) can be written as


x+6y+11=0x+6y+11=0


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