Answer to Question #335782 in Calculus for Dhanush

Question #335782

Check whether limit of the function of f(x,y)=4x^5y/x^10+3y^2 exists as (x,y) tends to (0,0).


1
Expert's answer
2022-05-05T10:36:56-0400

If x=0x=0 then f(0,y)=0(y)0+3y2=0.f(0, y)=\dfrac{0(y)}{0+3y^2}=0. Therefore


f(x,y)0 as (x,y)(0,0) along the yaxisf(x, y)\to 0\text{ as} \ (x,y)\to(0,0) \text{ along the }y-\text{axis}

For all x0x\not=0


f(x,x5)=4x5(x5)x10+3(x5)2=10f(x, x^5)=\dfrac{4x^5(x^5)}{x^{10}+3(x^5)^2}=1\not=0

f(x,y)10 as (x,y)(0,0) along y=x5f(x, y)\to 1\not=0\text{ as} \ (x,y)\to(0,0) \text{ along }y=x^5

Since we have obtained different limits along different paths, limit


lim(x,y)(0,0)f(x,y)=lim(x,y)(0,0)4x5yx10+3y2\lim\limits_{(x,y)\to(0,0)}f(x, y)=\lim\limits_{(x,y)\to(0,0)}\dfrac{4x^5y}{x^{10}+3y^2}

does not exist.



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