Locate the centroid of the volume bounded by the equation y^2 = 4x, x = 1 and the x-axis and revolving about the x-axis.
The equations for calculating the centroidal coordinates of a volume of arbitrary shape are given as
"\\overline{x}=\\frac{\\displaystyle\\int_V xdV}{\\displaystyle\\int_V dV}=\\frac{\\displaystyle\\int_V xdV}{\\displaystyle V}"
"\\overline{y}=\\frac{\\displaystyle\\int_V ydV}{\\displaystyle\\int_V dV}=\\frac{\\displaystyle\\int_V ydV}{\\displaystyle V}"
"\\overline{z}=\\frac{\\displaystyle\\int_V zdV}{\\displaystyle\\int_V dV}=\\frac{\\displaystyle\\int_V zdV}{\\displaystyle V}"
Let's find "\\overline{x}":
"y^2=4x" , "x=1"
"y=\\pm2\\sqrt x" , "0\\le x\\le1"
"dV=\\pi y^2(x)dx=\\pi (2\\sqrt x)^2dx=\\pi\\cdot4xdx"
"\\displaystyle\\int_V xdV=\\displaystyle\\int_0^1 x\\pi\\cdot4xdx=\\frac43\\pi x^3|_0^1=\\frac43\\pi"
Volume can be found using the formula:
"V=\\displaystyle\\int_V dV=\\pi\\displaystyle\\int_0^1y^2(x)dx=\\pi\\displaystyle\\int_0^1(2\\sqrt x)^2dx""=\\pi\\displaystyle\\int_0^14xdx=\\pi\\cdot2x^2|_0^1=2\\pi"
"\\overline{x}=\\frac{\\displaystyle\\int_V xdV}{\\displaystyle\\int_V dV}=\\displaystyle\\frac43\\pi\/(2\\pi)=\\frac23"
No necessary to calculate "\\overline{y}" and "\\overline{z}" . Since the body is obtained by rotation around the x axis, it means that it is symmetrical along the x axis and the centroid point will lie on the x axis. Therefore we can conclude
"\\overline{y}=0"
"\\overline{z}=0"
Answer: Coordinates of the centroid: ("\\frac23,0,0)" .
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