The speed(v) of car in m/s is related to time t in second by the equation: v= 3+12t-3t^ . Find the maximum of the car in km/h?
"\\frac{dv}{dt}=0 \\to 12-6t=0 \\to t=2."
"v_{max}=v(2)=3+12*2-3*2^2=15 \\frac{m}{s}."
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