Answer to Question #326708 in Calculus for MUTABAZI Valens

Question

The speed(v) of car in m/s is related to time t in second by the equation: v= 3+12t-3t^ . Find the maximum of the car in km/h?

Answer 1

$\frac{dv}{dt}=0 \to 12-6t=0 \to t=2.$

$v_{max}=v(2)=3+12*2-3*2^2=15 \frac{m}{s}.$