Write the series 2 + 9 + 28 + 65 + ⋯ in Sigma notation.
2=13+19=23+128=33+165=43+12+9+28+65+...=∑n=1∞(n3+1)2=1^3+1\\9=2^3+1\\28=3^3+1\\65=4^3+1\\\\2+9+28+65+...=\sum_{n=1}^{\infty}{\left( n^3+1 \right)}2=13+19=23+128=33+165=43+12+9+28+65+...=∑n=1∞(n3+1)
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