Question #326445

Find the volume of an object enclosed by cylinders z = y2 +2, z = 4−y2 and planes x = −1 and x = 2.



1
Expert's answer
2022-04-12T14:08:19-0400


Let's find the integration boundaries:

1x2-1\le x\le2 ;

to find the bounds for y equate y2+2y^2 +2 and 4y24-y^2 :

y2+2=4y2y^2+2=4-y^2

2y2=22y^2=2

y=±1y=\pm1

1y1-1\le y\le1

y2+2z4y2y^2+2\le z\le 4-y^2

V=12dx11dyy2+24y2dz=\displaystyle V=\int_{-1}^2dx\int_{-1}^1 dy\int_{y^2+2}^{4-y^2}dz=12dx11(4y2(y2+2))dy=\displaystyle \int_{-1}^2dx\int_{-1}^1 (4-y^2-(y^2+2))dy=12dx11(22y2)dy=\displaystyle \int_{-1}^2dx\int_{-1}^1 (2-2y^2)dy=12dx(2y23y3)11=8312dx=\displaystyle \int_{-1}^2dx (2y-\frac23y^3)|_{-1}^1=\displaystyle \frac83\int_{-1}^2dx =83(2(1))=8\displaystyle \frac83(2-(-1))=8

Answer: V=8V=8.


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