Question #320388

a ladder 20 feet long leans against a vertical building is the tower of the ladder slides down at a rate of p3 fits how fast is the bottom of the ladder sliding away from the building in the top of the ladder is 10 feet above the ground

Expert's answer

yheightabovethegroundxdistanceofthebottomtothewallx=202y2dydt=3dxdt=12202y2(2y)dydt=y400y2(3)==310400102=1.73205y-height\,\,above\,\,the\,\,ground\\x-dis\tan ce\,\,of\,\,the\,\,bottom\,\,to\,\,the\,\,wall\\x=\sqrt{20^2-y^2}\\\frac{dy}{dt}=-3\\\frac{dx}{dt}=\frac{1}{2\sqrt{20^2-y^2}}\cdot \left( -2y \right) \frac{dy}{dt}=-\frac{y}{\sqrt{400-y^2}}\cdot \left( -3 \right) =\\=\frac{3\cdot 10}{\sqrt{400-10^2}}=1.73205\,\,


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