Question #320380

Find 𝑑𝑦 𝑑𝑥 if 𝑥 2𝑦 + 2𝑦 3 = 3𝑥 + 2𝑦


1
Expert's answer
2022-04-05T16:38:53-0400

x2y+2y3=3x+2yx²y+2y³=3x+2y


2xy+x2dydx+6y2dydx=3+2dydx2xy+x²\frac{dy}{dx}+6y²\frac{dy}{dx}=3+2\frac{dy}{dx}


x2dydx+6y2dydx2dydx=2xy+3x²\frac{dy}{dx}+6y²\frac{dy}{dx}-2\frac{dy}{dx}=-2xy+3


(x2+6y22)dydx=32xy(x²+6y²-2)\frac{dy}{dx}=3-2xy


dydx=32xyx2+6y22\frac{dy}{dx}=\frac{3-2xy}{x²+6y²-2}




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