Find 𝑑𝑦 𝑑𝑥 if 𝑥 2𝑦 + 2𝑦 3 = 3𝑥 + 2𝑦
x2y+2y3=3x+2yx²y+2y³=3x+2yx2y+2y3=3x+2y
2xy+x2dydx+6y2dydx=3+2dydx2xy+x²\frac{dy}{dx}+6y²\frac{dy}{dx}=3+2\frac{dy}{dx}2xy+x2dxdy+6y2dxdy=3+2dxdy
x2dydx+6y2dydx−2dydx=−2xy+3x²\frac{dy}{dx}+6y²\frac{dy}{dx}-2\frac{dy}{dx}=-2xy+3x2dxdy+6y2dxdy−2dxdy=−2xy+3
(x2+6y2−2)dydx=3−2xy(x²+6y²-2)\frac{dy}{dx}=3-2xy(x2+6y2−2)dxdy=3−2xy
dydx=3−2xyx2+6y2−2\frac{dy}{dx}=\frac{3-2xy}{x²+6y²-2}dxdy=x2+6y2−23−2xy
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