Region bounded by the curve y2=x3 and the x-axis, is revolved about the line y=2.
Point of interception
22=x3 ; x=41/3
Let's move to new coordinates:
u=y−2t=x
Now region is revolved about the line u=0
(u+2)2=t3
u=t3/2−2
The required volume can be obtained by subtracting volume A
A=∫041/3π(t3/2−2)2dt
from volume B
B=∫041/3π(−2)2dt=∫041/3π22dt .
V=B−A=∫041/3π(22−(t3/2−2)2)dt=∫041/3π(−t3+4t3/2)dt=π(−4t4+58t5/2)∣041/3=π(−444/3+5845/6)=5π⋅41/3⋅11≈10.97
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