Answer to Question #316861 in Calculus for jash

Question #316861

drug response curve describes the level of medication in the bloodstream after a drug is administered. A surge function S(t) = Atpekt

 (where t > 0) is often used to model the response curve, reflecting an initial surge in the drug level and then a more gradual decline. If, for a particular drug, A = 0.03, p = 4, k = 0.05, and t is measured in minutes, estimate the times t corresponding to the inflection points. (Round your answers to two decimal places.)t = min (smaller value) t = min (larger value)


1
Expert's answer
2022-03-24T13:30:08-0400

S(t)=Atpekt=0.03t4e0.05tS(t)=At^pe^{-kt}=0.03\cdot t^4\cdot e^{-0.05t}; t>0t>0

Find inflection points.

Solution:

Inflection points can only occur when the second derivative is zero or undefined.

Here we have:

S(t)=0.034t3e0.05t0.030.05t4e0.05t=S'(t)=0.03\cdot 4t^3e^{-0.05t}-0.03\cdot 0.05t^4e^{-0.05t}=0.03e0.05tt3(40.05t)0.03e^{-0.05t}t^3( 4-0.05t);

S(t)=0.030.05e0.05tt3(40.05t)+S''(t)=-0.03\cdot 0.05e^{-0.05t}t^3( 4-0.05t)+ 0.033e0.05tt2(40.05t)0.03\cdot 3e^{-0.05t}t^2( 4-0.05t)-0.030.05e0.05tt3=0.03\cdot 0.05e^{-0.05t}t^3= t2e0.05t(0.000075t20.012t+0.36)t^2\cdot e^{-0.05t}( 0.000075t^2-0.012t+0.36);

t2e0.05t(0.000075t20.012t+0.36)=0t^2\cdot e^{-0.05t}( 0.000075t^2-0.012t+0.36)=0

Therefore possible inflection points occur at

t=40t=40 and t=120t=120; (t=0t=0 not interested because we are looking for inflection points only for t>0t>0 ).

However, to have an inflection point we must check that the sign of the second derivative is different on each side of the point. Here we have

S(10)15.01S''(10)\approx 15.01;

S(100)6.06S''(100)\approx-6.06;

S(150)3.08S''(150)\approx3.08.

Hence, both are inflection points.

Answer: there are two inflection points t=40t=40.00 and t=120t=120.00 .


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