(i)Find the volume of the solid that is generated by revolving the region bound by the
graphs of 𝑦 = 𝑥2 and 𝑦2 = 𝑥 about the 𝑦 − 𝑎𝑥𝑖𝑠.
V=π∫01((y)2−(y2)2)dy=V=\pi\int_0^1 ((\sqrt y)^2-(y^2)^2)dy=V=π∫01((y)2−(y2)2)dy=
π∫01(y−y4)dy=π(y2/2−y5/5)∣01=\pi\int_0^1 (y-y^4)dy=\pi(y^2/2-y^5/5)|_0^1=π∫01(y−y4)dy=π(y2/2−y5/5)∣01=
π(1/2−1/5)=3π10\pi(1/2-1/5)=\frac{3\pi}{10}π(1/2−1/5)=103π
Answer: V=3π10V= \frac{3\pi}{10}V=103π .
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