Answer to Question #281746 in Calculus for Nisha

Question #281746

[C] Find the Wronskian of the following functions and determine whether it is linearly dependent or linearly independent on (-∞,∞).

  1. {x2, x+1, x-3}               ans, W=8, linearly independent
  2. {3e2x, e2x}                     ans, W=0, linearly dependent
  3. {x2, x3, x4}                    ans, W=2x^6, linearly independent
1
Expert's answer
2021-12-26T17:41:45-0500

Let us find the Wronskian of the following functions and determine whether it is linearly dependent or linearly independent on "(-\u221e,\u221e)."


1.   "\\{x^2, x+1, x-3\\}"

Since


"W(x^2, x+1, x-3)=\n\\begin{vmatrix}\nx^2 & x+1 & x-3\\\\\n2x & 1 & 1\\\\\n2 & 0 & 0\n\\end{vmatrix}\n\\\\=2(x+1)-2(x-3)=2x+2-2x+6=8\\ne 0,"


we conclude that the functions are  linearly independent.


2.   "\\{3e^{2x}, e^{2x}\\}"

         Since


"W(3e^{2x}, e^{2x})=\n\\begin{vmatrix}\n3e^{2x} & e^{2x}\\\\\n6e^{2x} & 2e^{2x}\n\\end{vmatrix}\n=6e^{4x}-6e^{4x}= 0,"


we conclude that the functions are  linearly dependent.   

 

3.   "\\{x^2, x^3, x^4\\}"

        Since


"W(x^2, x^3, x^4)=\n\\begin{vmatrix}\nx^2 & x^3 & x^4\\\\\n2x & 3x^2 & 4x^3\\\\\n2 & 6x & 12x^2\n\\end{vmatrix}\n\\\\=36x^6+8x^6+12x^6-6x^6-24x^6-24x^6=2x^6\\ne 0,"


we conclude that the functions are  linearly independent.          


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