Question #281704

If fie=2x+2, evaluate volume integral where R is the region of the cube bounded by the plane x=0 ,x=1, y=0, y=1 ,z=0, z=1


1
Expert's answer
2021-12-22T03:32:43-0500
010101(2x+2)dzdxdy\displaystyle\int_{0}^1\displaystyle\int_{0}^1\displaystyle\int_{0}^1(2x+2)dzdxdy

=0101(2x+2)dxdy=\displaystyle\int_{0}^1\displaystyle\int_{0}^1(2x+2)dxdy

=01[x2+2x]10dy=\displaystyle\int_{0}^1[x^2+2x]\begin{matrix} 1 \\ 0 \end{matrix}dy

=013dy=3=\displaystyle\int_{0}^13dy=3


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