Question #260837

5) The displacement, 𝑦(m), of a body in damped oscillation is

π’š = πŸπ’† βˆ’π’• 𝐬𝐒𝐧 πŸ‘π’•

a) Use the Product Rule to find an equation for the velocity of the object if 𝑣 = 𝑑𝑦 𝑑𝑑


6) You are given the following function which describes the readout taken from an oscilloscope

𝑦 = 3cos (2π‘₯)

Your tasks are to:

a) Create a graph showing 2 full periods of the function

b) Take two gradients from the graph

c) Differentiate the function and prove your answers from part b using calculus

d) Compare your answers 


Expert's answer

5)

v(t)=yβ€²(t)=βˆ’2eβˆ’tsin3t+6eβˆ’tcos3tv(t)=y'(t)=-2e^{-t}sin3t+6e^{-t}cos3t


6)

a)



b)

gradients from the graph:

at point (1.1, -2):

Ξ”y/Ξ”x=βˆ’1.5/0.4=βˆ’3.75\Delta y/\Delta x=-1.5/0.4=-3.75

at point (5.1, -2):

Ξ”y/Ξ”x=1.4/0.4=3.5\Delta y/\Delta x=1.4/0.4=3.5


c)

yβ€²=βˆ’6sin(2x)y'=-6sin(2x)

yβ€²(1.1)=βˆ’4.85y'(1.1)=-4.85

yβ€²(5.1)=4.20y'(5.1)=4.20


d)

error at point (1.1, -2):

4.85βˆ’3.754.85=22.7%\frac{4.85-3.75}{4.85}=22.7\%


error at point (5.1, -2):

4.2βˆ’3.54.2=16.67%\frac{4.2-3.5}{4.2}=16.67\%


to compare results it was used formula for relative error:


∣grtβˆ’grg∣grt\frac{|gr_t-gr_g|}{gr_t}


where grt is gradient from theoretical calculations,

grr is gradient from graph


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