2. Two functions f and g are defined on the set R, of real numbers by
f:x-> 2x - 3 or f:x-> 2x-3/x
x
and
g : x -> 1- 3x OR g:x-> 1- 3x/2 Find the inverse of the function f and the domain of gof.
2
1.The length of a plant each week form an geometric sequence with "b{\\scriptscriptstyle 1}=1.67" and q = 1.02
We have to find the sum of the first 20 elements of this sequence. The formula of the first n elements is:
"S{\\scriptscriptstyle n}={\\frac{b{\\scriptscriptstyle 1}*(1-q^{n})} {1-q}}"
In our case: "S{\\scriptscriptstyle 20}={\\frac{1.67*(1.02^{20}-1)} {1.02-1}} = 124.07" cm
2. f:x-> 2x - 3
f(x) = 2x-3. To find it inverse we should express x in terms of f(x): "x={\\frac{f(x)+3} 2}"
The inverse of this function is "f^{-1}: x\\to{\\frac{x+3} 2}"
g : x -> 1- 3x
(gof)(x) = 1-3(2x-3) = 1-6x+9. The domain of this function is x є R
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