Answer to Question #221110 in Calculus for Marvellous

Question

An curve has equation y =12/3 -2x

Find dy/dx

Answer 1

$y = \dfrac{12}{3-2x}$

$u = 12 \\ du/dx= 0 \\ v = 3- 2x \\ dv /dx = -2$

from, $\dfrac{dy}{dx}=\dfrac{V\dfrac{du}{dx}- U\dfrac{dv}{dx} }{V²}$

$\dfrac{dy}{dx} =\dfrac{(3-2x)(0)- 12(-2) }{(3-2x)²}$

$\dfrac{dy}{dx} =\dfrac{24}{(3-2x)²}$