Question #215104
Ques:1
1. Find r ′ and T for r = ht 2 , 1, ti
2. Find r ′ and T for r = hcos t, sin 2t, t2 i.
1
Expert's answer
2021-07-09T09:43:04-0400

Solution;

1.Find r' and T for r=ht2,1,ti

r'=ddt\frac {d}{dt} r=2ht,0,i

T=rr\frac{r'}{|r'|}

r=(2ht)2+02+i2=4h2t21|r'|=\sqrt{(2ht)^2+0^2+i^2}=\sqrt{4h^2t^2-1}

T=2ht4h2t21,0,i4h2t21\frac{2ht}{\sqrt{4h^2t^2-1}},0,\frac{i}{\sqrt{4h^2t^2-1}}

2.Find r' and T for r=hcost ,sin2t ,t2i

r'=ddt\frac{d}{dt}r=-hsint,2cos2t,2it

T=rr\frac{r'}{|r'|}

r=(hsint)2+(2cos2t)2+(2it)2|r'|=\sqrt{(-hsint)^2+(2cos2t)^2+(2it)^2} =h2sin2t+4cos2(2t)4t2\sqrt{h^2sin^2t+4cos^2(2t)-4t^2}

T=hsinth2sin2t+4cos2(2t)4t2,\frac{-hsint}{\sqrt{h^2sin^2t+4cos^2(2t)-4t^2}}, 2cos2th2sin2t+4cos2(2t)4t2,\frac{2cos2t}{\sqrt{h^2sin^2t+4cos^2(2t)-4t^2}}, 2ith2sin2t+4cos2(2t)4t2\frac{2it}{\sqrt{h^2sin^2t+4cos^2(2t)-4t^2}}


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