Solution:
y=4sin2x+3cos(1/2 x)
On differentiating both sides w.r.t x,
dxdy=4cos2x.(2)+3(−sin(21 x)).(21)=8cos2x−23(sin21x)
Put x=3π
dxdy=8cos2(3π)−23(sin21.3π)=8cos(32π)−23(sin6π)=8(2−1)−23(21)=−4.75
So, the gradient of y at x=3π is −4.75.
Comments
Leave a comment