Question

limit as x tends to 2,(root of 6-x, minus 2) all over (root of 3-x, minus 1)

Answer 1

$lim_{x\to 2}\frac{\sqrt{6-x}-2}{\sqrt{3-x}-1}\newline Putting x=2,\newline =\frac{\sqrt{4}-2}{\sqrt{1}-1}\newline =\infty$

Thus, the limit of the given function is $\infty$ .