Given:
x=t−4y=t2+5
So to find equation of the curve we start with y,
and using a basic conversion in the given equation,
y=t2+5y=t2+5−16+16y=(t2−16)+21y=(t−4)(t+4)+21y=(t−4)(t−4+8)+21
Now putting,
x=t−4
we further get,
y=x(x+4)+21y=x2+8x+21 .............is the required curve. Now plotting on the graph
–1 ≤ t ≤ 2
we get,

This graph represents the given parametric equations.