Answer to Question #175730 in Calculus for Shahir Sheikh

Question

A particle moves in the xy-plane with the position given by the parametric equations:

x = t^3-t^2-9t +9

y = 2-t

Find the location of the particle when t = 1.

(_,_)

Answer 1

A particle moves in the xy-plane with the position given by the parametric equations:

x(t) = t³ - t² - 9t + 9

y(t) = 2 - t

we have to find the location of the particle when t = 1.

$\implies$ x(1) = 1³ - 1² - 9$\cdot$1 + 9

x(1) = 1 - 1 - 9 + 9

x(1) = 0

$\implies$ y(1) = 2 - 1

y(1) = 1

hence,

Location of the particle at t = 1 is (0,1)